ilaiyaraja
14th November 2012 15:26 UTC

Run an application using short cut folder in StartMenu in nsis?
How to start the my application using short cut in Start menu? I have tried following but could not started the application?


CreateShortcut "$STARTMENU\Programs\my application\my app.lnk" "$INSTDIR\setup.exe" "" "" 0

In my script i did not included setup.exe? After compiling only setup.exe file created.Is there need to copy this file? I dont know how to solve this?

Can anyone help me?

MSG
14th November 2012 15:43 UTC

I'm not sure if I understand your question correctly, but if you want to create a shortcut to your installed application, the code should look something like this:
CreateShortCut "$SMPROGRAMS\My Company\My Program.lnk" "$INSTDIR\My Program.exe" "" "$INSTDIR\My Program.exe"

If you want to create a shortcut to the installer (why??), you could try:
CreateShortCut "$SMPROGRAMS\My Company\My Program Setup.lnk" "$EXEPATH" "" "$EXEPATH"
(Of course this assumes that the installer isn't renamed, deleted or moved after installation.)

ilaiyaraja
15th November 2012 04:26 UTC

CreateShortCut "$SMPROGRAMS\My Company\My Program Setup.lnk" "$EXEPATH" "" "$EXEPATH"

If i give it'll open the output directory.I need to run my application through this short cut menu?

MSG
15th November 2012 05:41 UTC

You're still not clearly saying what you want to run: Your installer, or your application?

ilaiyaraja
15th November 2012 05:52 UTC

Thanks MSG.

I need to run my application through this shortcut option.No need to run the installer.

MSG
15th November 2012 06:12 UTC

Then you shouldn't be bothering with $EXEPATH. Like I said, that's if you wanted to run the installer itself.