Get file from its path

How can I get the file from a path?
For example:
The path of a file is:
C:\Windows\system32\calc.exe
I wanna retrive only the file "calc.exe"

If the full path is:
C:\Windows\explorer.exe
I wanna retrive the file "explorer.exe"

Is it possible?

Thanks.

Use this:


-Stu

Great 👍
Can be use with Internet urls?

In the script replace \ with /

-Stu

Yes! Thanks, man 🙂